-19x=16x^2

Solution for -19x=16x^2 equation:

-19x=16x^2

We move all terms to the left:

-19x-(16x^2)=0

determiningTheFunctionDomain
-16x^2-19x=0

a = -16; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·(-16)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*-16}=\frac{0}{-32}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*-16}=\frac{38}{-32}
=-1+3/16
$